Well that stuff in the previous post leads us nicely on to the factor theorem. Although this sounds like a low budget 70s sci-fi drama, it is in fact a key part of A Level maths.
The factor theorem is dead simple. If you have a polynomial x3 + 6x2 + 11x + 6, it has factors, namely a linear and a quadratic.
Only this time, the quadratic itself factorises, so that the cubic has 3 linear factors, namely (x+1)(x+2)(x+3).
If I now did something a bit sneaky, I could prove that these are factors of this cubic.
Watch. P(-1) = -13 + 6(-12) + 11(-1) + 6
= -1 + 6 - 11 + 6
= 0
When x=-1 the cubic equation = 0.
This proves that (x+1) is a factor of x3 + 6x2 + 11x + 6
In fact, if (x-a) is a factor of P(x) then P(a) = 0. Always and everywhere.
Why?
Well, look at (x+1)(x+2)(x+3).
These are all factors of x3 + 6x2 + 11x + 6.
So if you put x= -1 into the first factor, it will equal 0 (-1+1) and therefore the whole polynomial will equal 0. The same goes for all the other factors.
If a value, a, put into P(x) does not equal 0, then (x-a) IS NOT a factor.
Saturday, 6 September 2008
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