The equation of the (straight) line isn't difficult. In fact it's dead easy.
The reason is this. Any curve or line has a statement that describes what happens to a y-co-ordinate when you plug in a given x-value. This is why we talk of f(x), because the y co-ordinate is basically the function of the x under certain conditions, which differ for various lines and curves. With this statement you have the potential to describe the co-ordinates of the curve or line completely knowing only the x-value.
The equation is simply the statement of what happens to the y co-ordinate when you select any x co-ordinate you like. It contains the gradient of the line within it, because clearly where the y-value is will depend on how steep the line is.
We often hear about y=mx + c , where m=gradient, and c= y-intercept (or where the line crosses the y-axis).
It is fine and dandy, to be sure.
But for MPC1 purposes the following equation is also useful, not least because solving it leads to y=mx+c.
(y - y1) = m(x - x1)
Where (x,y) is any, unknown point on the line and (x1, y1) is a known point.
For example: take a line passing through (2,4) and (6,10).
Firstly, work out m. 6/4. or 3/2.
Plug that into the equation: (y-4) = 3/2(x-6) or y-4 = 3/2x - 9 or y= 3/2x -5.
Suddenly you have your y-intercept (-5) and your y =mx+c.
The only thing is, you need the gradient, so you need to know two points on the line from the start.
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