Thursday 22 January 2009

Indices And Differentiation

Yesterday, courtesy of my beautiful and awesomely intelligent maths tutor, I suddenly worked out a way of making differentiation with negative indices slightly easier.

When inputting the x value to find the gradient at that point, to make the final stage of adding it all up much easier, turn your x-2 into 1/x2. It makes calculations a lot, lot easier.

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